破解excel的vba工程保护密码
【破解excel的vba工程保护密码】新建一个excel，将以下代码复制在一个新模块。这个里面有两个宏，一个是破除密码，一个是重置密码。
Sub MoveProtect()
Dim FileName As String
FileName = Application.GetOpenFilename("Excel文件（*.xls & *.xla）,*.xls;
*.xla", , "VBA破解")
If FileName = CStr(False) Then
Exit Sub
Else
VBAPassword FileName, False
End If
End Sub'设置VBA编码保护
Sub SetProtect()
Dim FileName As String
FileName = Application.GetOpenFilename("Excel文件（*.xls & *.xla）,*.xls;
*.xla", , "VBA破解")
If FileName = CStr(False) Then
Exit Sub
Else
VBAPassword FileName, True
End If
End SubPrivate Function VBAPassword(FileName As String, Optional Protect As Boolean = False)
If Dir(FileName) = "" Then
Exit Function
Else
FileCopy FileName, FileName & ".bak"
End IfDim GetData As String * 5
Open FileName For Binary As #1
Dim CMGs As Long
Dim DPBo As Long
For i = 1 To LOF(1)
Get #1, i, GetData
If GetData = "https://www.it610.com/article/CMG=""" Then CMGs = i
If GetData = "https://www.it610.com/article/[Host" Then DPBo = i - 2: Exit For
Next
If CMGs = 0 Then
MsgBox "请先对VBA编码设置一个保护密码...", 32, "提示"
Exit Function
End If
If Protect = False Then
Dim St As String * 2
Dim s20 As String * 1
'取得一个0D0A十六进制字串
Get #1, CMGs - 2, St
'取得一个20十六制字串
Get #1, DPBo + 16, s20
'替换加密部份机码
For i = CMGs To DPBo Step 2
Put #1, i, St
Next
'加入不配对符号
If (DPBo - CMGs) Mod 2 <> 0 Then
Put #1, DPBo + 1, s20
End If
MsgBox "文件解密成功......", 32, "提示"
Else
Dim MMs As String * 5
MMs = "DPB="""
Put #1, CMGs, MMs
MsgBox "对文件特殊加密成功......", 32, "提示"
End If
Close #1
End Function推荐阅读
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